Make tests that wait for concurrent work wait on the event or a condition with a long deadline (issue 1814)
A test that slept a fixed time and then asserted what a goroutine, process or watcher did failed under the checker's load. Each now waits for its positive evidence (a started baseline, a call counted, a state reached) within 30 s, and the concurrency-limit tests meet at a barrier instead of overlapping by sleep. Claude-Session: https://claude.ai/code/session_01NcbgfJ9Gum47zkFKWRaovL
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@@ -26,11 +26,11 @@ func TestATimedOutCommandIsEndedWithItsChildren(t *testing.T) {
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KillGrace = 300 * time.Millisecond
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defer func() { KillGrace = old }()
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pidFile := filepath.Join(t.TempDir(), "child")
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ctx, cancel := context.WithTimeout(context.Background(), 300*time.Millisecond)
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ctx, cancel := context.WithTimeout(context.Background(), 3*time.Second) // long enough for a loaded machine to start the shell and write the pid
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defer cancel()
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start := time.Now()
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r := ExecRunner(ctx, "sh", "-c", "sleep 30 & echo $! > "+pidFile+"; wait")
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if took := time.Since(start); took > 5*time.Second {
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if took := time.Since(start); took > 30*time.Second {
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t.Fatalf("the call waited %s for a child holding its output", took)
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}
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if !r.TimedOut {
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@@ -41,7 +41,9 @@ func TestATimedOutCommandIsEndedWithItsChildren(t *testing.T) {
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t.Fatal(err)
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}
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pid, _ := strconv.Atoi(strings.TrimSpace(string(b)))
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time.Sleep(100 * time.Millisecond)
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// the kill is sent before the answer; give the system up to 30 s to take the child away
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for end := time.Now().Add(30 * time.Second); time.Now().Before(end) && syscall.Kill(pid, 0) == nil; time.Sleep(10 * time.Millisecond) {
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}
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if err := syscall.Kill(pid, 0); err == nil {
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syscall.Kill(pid, syscall.SIGKILL)
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t.Errorf("the child %d outlived the timeout", pid)
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