package compose import ( "fmt" "sort" ) // CredentialKey names one pair credential by the ends it joins: the provision, the consumer's node and module, the // provider's node, and the local name where a module keeps several (Credential's and Issued's key). type CredentialKey struct { Provision string `json:"provision"` Consumer string `json:"consumer"` ConsumerModule string `json:"consumer_module"` Provider string `json:"provider"` Local string `json:"local,omitempty"` } // CredentialsNeeded is every pair credential node's composition reads (novox/hq ADR 0547 §2, ADR 0550 §5, issue 1126): // as a consumer, each need of its resolution a provider's credential answers (a need answered by a record is a licence's, // not a pair's); as a provider, each credential it must carry a grant for (rowsFor). A node that composes its own asks the // vault for exactly these, sealed to its key, and composes with them; one it does not get is stood in for, which the // node's own apply refuses (CompositionsApplied). func CredentialsNeeded(in Input, node string) (asConsumer, asProvider []CredentialKey, err error) { c := newComposer(in) resolved, err := c.resolution(node) if err != nil { return nil, nil, err } for _, n := range resolved.Needs { if n.ByRecord || n.From == "" { continue } asConsumer = append(asConsumer, CredentialKey{Provision: n.Name, Consumer: node, ConsumerModule: n.For, Provider: n.From, Local: n.Local}) } rows, err := c.rowsFor(node) if err != nil { return nil, nil, fmt.Errorf("compose: the credentials %s provides: %w", node, err) } for _, r := range rows { asProvider = append(asProvider, CredentialKey{Provision: r.Provision, Consumer: r.Consumer, ConsumerModule: r.ConsumerModule, Provider: node, Local: r.Local}) } sortKeys(asConsumer) sortKeys(asProvider) return asConsumer, asProvider, nil } func sortKeys(ks []CredentialKey) { sort.Slice(ks, func(i, j int) bool { a, b := ks[i], ks[j] switch { case a.Provision != b.Provision: return a.Provision < b.Provision case a.Provider != b.Provider: return a.Provider < b.Provider case a.Consumer != b.Consumer: return a.Consumer < b.Consumer case a.ConsumerModule != b.ConsumerModule: return a.ConsumerModule < b.ConsumerModule } return a.Local < b.Local }) }